![]() ![]() Since the tank is in the shape of a triangle, the width of the tank at a given depth can be found using similar triangles. Step 3: Determine the width of the tank at a given depth For water, the density is approximately 62.4 lb/ft³, and the acceleration due to gravity is approximately 32.2 ft/s². The pressure at a given depth in a fluid is given by the formula P = ρgh, where ρ is the density of the fluid, g is the acceleration due to gravity, and h is the depth. Step 2: Determine the pressure at a given depth Let's denote the height of the tank as h. The fluid force on the window is about 1608.5 pounds.Since the tank is full of water, the depth of the water is equal to the height of the triangular tank. ![]() Observing the first integral is a semicircle's area with radius 1 produces The second integral is 0 because the integrand is odd and the integration limits are symmetric to the origin. The fluid force on a submerged horizontal surface with area \(A\) is Figure 7.7.2 show the pressure at each depth is the same for all three objects. ![]() Pascal’s Principle states that the pressure exerted by a fluid at a depth \(h\) is transmitted equally in all directions. When calculating fluid pressure, you can use an important physical law called Pascal’s Principle, named after the French mathematician Blaise Pascal. ![]() Where \(w\) is the liquid's weight-density per volume unit.īelow are weight-densities for common fluids in pounds per cubic foot. The pressure on an object at depth \(h\) in a liquid is At 30 feet below sea level the pressure is 30 pounds per square inch. At sea level the atmospheric pressure is 15 pounds per square inch. It is measured in pounds per square inch or kilograms per square centimeter. Pressure is the force on a body's surface area. At sea level 15 pound presses on the one inch square and one kilogram presses on the one centimeter square. ![]()
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